Comments on: Cystic Fibrosis Is a Genetic Disease of Humans Caused by Homozygosity for a Recessive Gene (Aa)? http://whatiscysticfibrosis.org/cystic-fibrosis/cystic-fibrosis-is-a-genetic-disease-of-humans-caused-by-homozygosity-for-a-recessive-gene-aa THE FACTS ABOUT CYSTIC FIBROSIS Thu, 25 Aug 2011 19:02:00 +0000 hourly 1 http://wordpress.org/?v=3.3.2 By: Abu http://whatiscysticfibrosis.org/cystic-fibrosis/cystic-fibrosis-is-a-genetic-disease-of-humans-caused-by-homozygosity-for-a-recessive-gene-aa/comment-page-1#comment-1055 Abu Sat, 31 Jul 2010 17:02:11 +0000 http://whatiscysticfibrosis.org/cystic-fibrosis/cystic-fibrosis-is-a-genetic-disease-of-humans-caused-by-homozygosity-for-a-recessive-gene-aa#comment-1055 In large popuation (Hardy Weinberg equillibrium): p^2 + 2pq + q^2 = 1; and p + q = 1 where: p^2 = freq. of dominant homozygous (AA) 2pq = freq. of heterozygous (Aa) q^2 = freq. of recessive homozygous (aa) From the data: q^2(aa) = 1/3600 = 0.00028 q(a) = SQRT 0.00028 = 0.017 p(A) = 1 - 0.017 = 0.983 2pq(Aa) = 2 x 0.983 x 0.017 = 0.0328 With this frequency of heterozygous normal (Aa) couple in the population, they may produce an affected chlid 1 in 30*). *) 1/0.0328 = 30,48 In large popuation (Hardy Weinberg equillibrium):
p^2 + 2pq + q^2 = 1; and p + q = 1
where:
p^2 = freq. of dominant homozygous (AA)
2pq = freq. of heterozygous (Aa)
q^2 = freq. of recessive homozygous (aa)
From the data:
q^2(aa) = 1/3600 = 0.00028
q(a) = SQRT 0.00028 = 0.017
p(A) = 1 – 0.017 = 0.983
2pq(Aa) = 2 x 0.983 x 0.017 = 0.0328
With this frequency of heterozygous normal (Aa) couple in the population, they may produce an affected chlid 1 in 30*).

*) 1/0.0328 = 30,48

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